18 lines
756 B
Lua
18 lines
756 B
Lua
for _, force in pairs(game.forces) do
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if force.technologies["angels-sulfur-processing-4"] and force.technologies["angels-sulfur-processing-3"] then
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force.technologies["angels-sulfur-processing-4"].researched =
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force.technologies["angels-sulfur-processing-3"].researched
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force.technologies["angels-sulfur-processing-3"].researched =
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force.technologies["angels-sulfur-processing-2"].researched
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end
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if force.technologies["angels-coal-processing-3"] and force.technologies["angels-coal-processing-2"] then
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force.technologies["angels-coal-processing-3"].researched =
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force.technologies["angels-coal-processing-2"].researched
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end
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force.reset_recipes()
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force.reset_technologies()
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force.reset_technology_effects()
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end
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